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How many milliliters of a syrup having a specific gravity of 1.350 should be mixed with 3000 mL of a syrup having a specific gravity of 1.250 to obtain a product having a specific gravity of 1.310?

User Bes Ley
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To obtain a product with a specific gravity of 1.310, you should mix 4500 mL of a syrup with a specific gravity of 1.350 with 3000 mL of a syrup with a specific gravity of 1.250.

The specific gravity of a substance is the ratio of its density to the density of water. It serves as a measure of a substance's density compared to water. When mixing substances with different specific gravities, the resulting specific gravity of the mixture can be determined using a weighted average approach.

To find the required amount of the syrup with a specific gravity of 1.350, the following formula can be used:

V₁ = [(SG₂ - SGₘ) × V₂]/(SG₁ - SGₘ)

Where:

- V₁ = volume of syrup with SG 1.350

- SG₁ = specific gravity of syrup with SG 1.350

- V₂ = volume of syrup with SG 1.250

- SG₂ = Specific gravity of syrup with SG 1.250

- SGₘ = Specific gravity of the mixture

Using the given values:

V₁ = [(1.250 - 1.310) × 3000]/(1.350 - 1.310)

V₁ = (-0.060 × 3000)/(0.040)

V₁ = -180 × 0.04

V₁ = -4,500 mL

Thus to obtain a product with a specific gravity of 1.310, 4500 mL of a syrup with a specific gravity of 1.350 should be mixed with 3000 mL of a syrup with a specific gravity of 1.250.

User BC TUBE
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