Final answer:
The magnitude of the electric field halfway between the two charges is approximately 1.31 x 10^5 N/C.
Step-by-step explanation:
To calculate the magnitude of the electric field halfway between the two charges, we can use the formula:
E = k × |q1 - q2| / r
where:
- E is the magnitude of the electric field
- k is the electrostatic constant (9 × 10^9 N m^2/C^2)
- q1 and q2 are the charges
- r is the distance between the charges
In this case, q1 = 9.68 microcoulombs, q2 = 1.70 microcoulombs, and r = 8.25 meters. Plugging these values into the formula, we get:
E = (9 × 10^9 N m^2/C^2) × |9.68 × 10^-6 C - 1.70 × 10^-6 C| / (8.25 / 2)
Simplifying this expression, we find that the magnitude of the electric field halfway between the charges is approximately 1.31 × 10^5 N/C.