Question

A batter hits a foul ball. The 0.14- kg baseball that was approaching him at 48 m/s leaves the bat at 34 m/s in a direction perpendicular to the line between the batter and the pitcher. What is the magnitude of the impulse (in N.s) delivered to the baseball?

Answer 1

To find the magnitude of the impulse delivered to the baseball, use the impulse-momentum theorem and calculate the average force exerted on the baseball. Then, multiply the average force by the time interval over which it is applied to find the magnitude of the impulse. Plug in the given values to solve the problem.

Step-by-step explanation:

To find the magnitude of the impulse delivered to the baseball, we can use the impulse-momentum theorem which states that the change in momentum of an object is equal to the impulse applied to it. The impulse is calculated by multiplying the force exerted on the object by the time interval over which the force is applied. In this case, the average force acting on the baseball can be found by using the formula: Average force = (change in momentum) / (time interval) The momentum of an object is calculated by multiplying the mass of the object by its velocity. So, the change in momentum for the baseball can be found by subtracting its initial momentum from its final momentum. The magnitude of the impulse is equal to the magnitude of the average force multiplied by the time interval. Plugging in the given values, we have: Average force = (0.14 kg * 34 m/s - 0.14 kg * 48 m/s) / (0.017 s) Impulse magnitude = Average force * time interval