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The fundamental frequency of an open-open tube is 2000 Hz when the tube is filled with 0 ∘ C helium. What is its frequency when filled with 0 ∘ C air?

User Jishnu V S
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Final answer:

The fundamental frequency of an open-open tube depends on its length and the speed of sound in the medium. The frequency in air can be calculated using the formula f1 = (v_air / 2L), while the frequency in helium can be calculated using the formula f1 = (v_helium / 2L).

Step-by-step explanation:

The fundamental frequency of a tube is determined by its length, temperature, and the speed of sound in the medium. The formula to calculate the fundamental frequency (f1) of an open-open tube is:

f1 = (v / 2L)

where v is the speed of sound and L is the length of the tube.

If the tube is filled with air at 0°C (273 K), the formula can be modified as:

f1_air = (v_air / 2L)

If the tube is filled with helium at 0°C, the formula becomes:

f1_helium = (v_helium / 2L)

Since the speed of sound in air at 0°C is approximately 331 m/s and the speed of sound in helium at 0°C is approximately 970 m/s, we can calculate the frequencies as follows:

f1_air = (331 / 2L)

f1_helium = (970 / 2L)

User Nick Roz
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