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Solve Graphically into the air from a launching p h=-16t²+72t+6.

User Ccl
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The time taken for the ball to reach maximum height when projected into the air from point P is 4.6 s.

How to calculate the time taken for the ball to reach maximum height?

The time taken for the ball to reach maximum height when projected into the air from point P is calculated as follows;

The given position function of the ball;

h(t) = -16t² + 72t + 6

From the graph, we can see that the time corresponding to the peak or the maximum height of the ball is approximately 4.6 seconds.

Thus, the time taken for the ball to reach maximum height when projected into the air from point P is h(t) = -16t² + 72t + 6.

The complete question is below:

Solve Graphically the time taken for the ball to reach maximum height when projected into the air from point, with position function of h = -16t² + 72t + 6.

Solve Graphically into the air from a launching p h=-16t²+72t+6.-example-1
User Wqw
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