Question

if a chavge q =−2e is traveling from vest to a point below its potential =2×10 3 V. Find the change in electrical potontial energy

Answer 1

The change in electrical potential energy when a charge of -2e moves through a potential difference of 2 × 103 V is -6.4 × 10-16 J.

Step-by-step explanation:

The change in electrical potential energy (ΔU) when a charge q moves through a potential difference ΔV can be calculated using the formula:

ΔU = q ΔV

In this case, we have a charge q = -2e (where e is the elementary charge, e = 1.6 × 10-19 C) moving through a potential difference of ΔV = 2 × 103 V. The change in electrical potential energy can be found by substituting these values into the formula, bearing in mind that two elementary charges are -2e = -2 × (1.6 × 10-19 C).

Here is the step by step calculation:

• ΔU = q ΔV
• ΔU = (-2 × 1.6 × 10-19 C) × (2 × 103 V)
• ΔU = -6.4 × 10-16 J

The negative sign indicates that the potential energy has decreased as the charge moved from a higher potential to a lower potential.