Question

A train slows down as it rounds a sharp horizontal turn, going from 88.0 km/h to 58.0 km/h in the 16.0 s that it takes to round the bend. The radius of the curve is 170 m. Compute the acceleration at the moment the train speed reaches 58.0 km/h.

Answer 1

The acceleration of the train at the moment its speed reaches 58.0 km/h is 1.52 m/s^2.

Step-by-step explanation:

To calculate the acceleration of the train at the moment its speed reaches 58.0 km/h, we can use the equation for centripetal acceleration: a = v^2 / r.

First, convert the speed from km/h to m/s by dividing by 3.6.

So, 58.0 km/h = 58.0/3.6 m/s = 16.1 m/s.

Then, plug in the values into the equation: a = (16.1^2) / 170.0 = 1.52 m/s^2.

Therefore, the acceleration of the train at the moment its speed reaches 58.0 km/h is 1.52 m/s^2.