Question

A driver of a car traveling at 15.0 m/s applies the brakes, causing a uniform acceleration of -2.0 m/s2. How long does it take the car to accelerate to a final speed of 10.0 m/s?

Answer 1

Using the kinematic equation, the car takes 2.5 seconds to decelerate from 15.0 m/s to 10.0 m/s with a uniform acceleration of -2.0 m/s^2.

Step-by-step explanation:

The duration it takes for a car to decelerate from 15.0 m/s to 10.0 m/s with a uniform acceleration of -2.0 m/s2 can be determined using the kinematic equation v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time. For this scenario, we know u = 15.0 m/s, v = 10.0 m/s, and a = -2.0 m/s2. By rearranging the equation to solve for t, we get t = (v - u) / a.

So, t = (10.0 m/s - 15.0 m/s) / (-2.0 m/s2) = -5.0 m/s / -2.0 m/s2 = 2.5 s.

Therefore, it takes the car 2.5 seconds to decelerate to the final speed of 10.0 m/s.