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An electromagnetic wave in vacuum has an electric field amplitude of Emax = 187.5 V/m. Calculate the amplitude Bmax of the corresponding magnetic field in units of nanoTesla.

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Final answer:

The amplitude of the magnetic field in an electromagnetic wave with a given electric field amplitude can be calculated using the formula Bmax = Emax / c, where Emax is the electric field amplitude and c is the speed of light in vacuum. In this case, the amplitude of the magnetic field is 625 nT.

Step-by-step explanation:

The amplitude of the magnetic field (Bmax) in an electromagnetic wave can be calculated using the formula Bmax = Emax / c, where Emax is the electric field amplitude and c is the speed of light in vacuum (~3 x 10^8 m/s).

Given Emax = 187.5 V/m, we can calculate Bmax as follows:

Bmax = 187.5 V/m / (3 x 10^8 m/s) = 6.25 x 10^(-10) T.

Therefore, the amplitude of the magnetic field in nanoTesla (nT) is 625 nT.

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