Question

A circular loop of radius 12,4 cm is placed in a uniform magnetic field. (3) If the field is directed perpendicular to the plane of the loop and the magnetic flux through the loop is 7.90×10⁻³ T−m² , what is the strength of the macetic field?

Answer 1

The strength of the magnetic field is calculated using the formula for magnetic flux, which is Φ = B × A. The area A of a circular loop is given by πr2, where r is the radius. By plugging in the given flux and radius, one can solve for the magnetic field strength B.

Step-by-step explanation:

The strength of the magnetic field B can be found using the formula for magnetic flux Φ, which is Φ = B × A, where A is the area of the loop. Since the loop is circular, A = π × r2, where r is the radius of the loop. We are given the flux Φ = 7.90× 10−3 T⋅m2 and the radius r = 12.4 cm = 0.124 m. Plugging in the values, we can solve for B.

Magnetic flux: Φ = 7.90× 10−3 T⋅m2
Area of the loop: A = π × (0.124 m)2
Now calculating the magnetic field,
Magnetic field: B = Φ / A = 7.90× 10−3 T⋅m2 / (π × (0.124 m)2)