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A 0.5kg ball moves in a circle that is 0.4m in radius at a speed of 5( m)/(s). Calculate its centripetal acceleration.

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Final answer:

The centripetal acceleration of a 0.5 kg ball moving in a circle of 0.4 m radius at a speed of 5 m/s is calculated using the formula ac = v^2 / r, resulting in a centripetal acceleration of 62.5 m/s^2.

Step-by-step explanation:

The question asks about the centripetal acceleration of a 0.5 kg ball moving in a circle with a radius of 0.4 m at a speed of 5 m/s. To calculate centripetal acceleration, we use the formula ac = v^2 / r, where ac is the centripetal acceleration, v is the speed, and r is the radius of the circular path.

Substituting the given values into the formula:

ac = (5 m/s)^2 / 0.4 m

ac = 25 m^2/s^2 / 0.4 m

ac = 62.5 m/s^2

Thus, the magnitude of the centripetal acceleration of the ball is 62.5 m/s^2.

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