Question

A pizza pan is removed at 9:00 PM from an oven whose temperature is fixed at 425°F in a room that is constant 74°F. After 5 minutes, the pizza pan is at 300 °F

at what time is the temperature of the pan 130°F ?

Answer 1

The temperature will be 130°F at 9.11.48 p.m

We need to calculate the change in temperature of the per minute ;

Change in temperature after 5 minutes = (425 - 300) = 125°F

Hence, the change in temperature per minute is ;

• 125 / 5 = 25° F per minute

Hence, temperature function is:

• T = -25x + 425

To attain a temperature of 130°F ;

130 = -25x + 425

25x = 425 - 130

25x = 295

x = 295/25

x = 11.8 minutes

The time : 9:00 + 11.8 minutes = 9.11.48 p.m