Final answer:
The 120µF capacitor charged by a 7.0V battery will store 0.84 mC (milliCoulombs) of charge.
Step-by-step explanation:
To calculate the charge stored in a capacitor when connected to a battery, we use the formula Q = C × V, where Q is the charge in coulombs, C is the capacitance in farads, and V is the voltage in volts provided by the battery.
For a 120µF capacitor charged by a 7.0V battery, the charge Q can be calculated as follows:
Q = 120µF × 7.0V
To find Q in coulombs, remember that 1µF = 1×10-6 F:
Q = (120 × 10-6 F) × 7.0V = 0.84 mC
Therefore, the 120µF capacitor will store 0.84 milliCoulombs (mC) of charge.