The force on an electron moving left to right in an upward-pointing 10T magnetic field, with a velocity of 1 m/s, is 1.6 x 10⁻¹⁸ N directed downward.
The question asks us to calculate the force magnitude and direction on an electron traveling horizontally in a vertical magnetic field. Using Lorentz force law, F = qvBsin(θ), where q is the charge of the electron (-1.6 x 10-19 C), v is the velocity of the electron (1 m/s), B is the magnetic field strength (10 T), and θ is the angle between the velocity and the magnetic field. Since the velocity is horizontal and the magnetic field is vertical, θ is 90 degrees, making sin(θ) = 1. Therefore, F = (-1.6 x 10-19 C) (1 m/s) (10 T)(1) = -1.6 x 10-18 N. The negative sign indicates the force direction is opposite to that determined by the right-hand rule, hence downward.