Question

Two speakers are attached to variable-frequency signal generator. Speaker A produces a constant-frequency sound wave of 1.000kHz, and speaker B produces a tone of 1.001kHz. The beat frequency is 0.001kHz. If the frequency of each speaker is doubled, what is the beat frequency produced?

Answer 1

When the frequency of both speakers is doubled, from 1.000 kHz and 1.001 kHz to 2.000 kHz and 2.002 kHz, respectively, the beat frequency produced will be 0.002 kHz or 2 Hz.

Step-by-step explanation:

The beat frequency is defined as the absolute difference in frequencies of two sounds. In the scenario provided, if we double the frequency of both Speaker A and Speaker B, we get:

Speaker A's doubled frequency: 1.000 kHz × 2 = 2.000 kHz

Speaker B's doubled frequency: 1.001 kHz × 2 = 2.002 kHz

The new beat frequency would now be the absolute difference between these two frequencies, which is:

Beat frequency = |2.002 kHz - 2.000 kHz| = 0.002 kHz or 2 Hz

the beat frequency produced when the frequency of each speaker is doubled will be 0.002 kHz or 2 Hz.