Final answer:
The resulting battery of cells connected in parallel will have an emf of 2 V and an internal resistance of 0.1 Ω.
Step-by-step explanation:
The question asks about the characteristics of a battery formed by connecting five cells in parallel, each cell with an emf of 2 V and internal resistance of 0.5 Ω. When cells are connected in parallel, the resulting emf is equal to the emf of a single cell, as the potential difference across each cell must be the same. However, the total internal resistance of the parallel combination is reduced, and can be found by taking the reciprocal of the sum of the reciprocals for each cell's internal resistance.
For the given cells, the total internal resistance Rt of n cells of internal resistance r connected in parallel is calculated as:
1/Rt = 1/r + 1/r + 1/r + 1/r + 1/r = 5/r
Rt = r/5 = 0.5 Ω / 5 = 0.1 Ω
Therefore, the resulting battery will have an emf of 2 V and an internal resistance of 0.1 Ω.