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A simple random sample from a population with a normal distribution of 102 body temperature has a x =98.30 F and a s =0.69 F. construct a 90% confidence interval estimate of the standard deviation of body temperature of all healthy humans.

User MoreFreeze
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Final answer:

To construct a 90% confidence interval estimate of the standard deviation of body temperature, you can use the t-distribution.

Step-by-step explanation:

To construct a 90% confidence interval estimate of the standard deviation of body temperature, you can use the t-distribution. The formula for the confidence interval is:

CI = (s * sqrt(n-1))/sqrt(chi-square value)

where s is the sample standard deviation, n is the sample size, and the chi-square value is determined based on the confidence level. Substituting the given values, the confidence interval can be calculated as CI = (0.69 * sqrt(101))/sqrt(chi-square value). You can look up the chi-square value for a 90% confidence level with 101 degrees of freedom in a chi-square table or use a statistical calculator.

User Hayward Oblad
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