Question

Supgore that 67 trkets are soid What is, the ptotrob 56 passeingers show up for the fight resuiting in an overbooked flight? (c) For a piane with seating capacity of 290 pasesongers whthat a passenger will have to be "bumped"? (a) The probability of an overbooked flight is 00165 (Round to four deamal places as neoded) (b) The probability that a passenger will have to be bumped is 04053 (Round to four decimal places as needed) (c) For a plane with seating capacily of 290 passengers, the largest number of tickets that can be sold while keeping the probability of a passenger being "bumped" bellow 1% is (Type a whole number)

Answer 1

To determine the number of passengers that will have to be bumped on an overbooked flight, we can use probability. The probability of an overbooked flight is 0.0165, and the probability that a passenger will have to be bumped is 0.4053. To keep the probability of a passenger being bumped below 1%, the largest number of tickets that can be sold on a plane with a seating capacity of 290 passengers is 2.

Step-by-step explanation:

To find the number of passengers that will have to be bumped on a flight, we need to determine the number of passengers that will show up for the flight and compare it to the seating capacity of the plane.

a) The probability of an overbooked flight is given as 0.0165, or 1.65% (rounded to four decimal places). This means that in 100 flights, approximately 1.65 flights will be overbooked.

b) The probability that a passenger will have to be bumped is given as 0.4053, or 40.53% (rounded to four decimal places).

c) To keep the probability of a passenger being bumped below 1%, we need to find the largest number of tickets that can be sold. Let's call this number x. We can set up the following equation: x/290 = 0.01. Solving for x, we find that x = 2.9. Since we cannot sell a fraction of a ticket, the largest number of tickets that can be sold while keeping the probability of a passenger being bumped below 1% is 2 tickets (rounded to the nearest whole number).