Final answer:
To find the number of copper atoms in 320 grams of copper sulfate (CuSO4), calculate the moles of CuSO4 and multiply by Avogadro's number. The calculation shows that there are approximately 1.206 × 10^24 copper atoms in 320 grams of copper sulfate.
Step-by-step explanation:
The question asks how many copper atoms are present in 320 grams of copper sulfate (CuSO4). To find the number of copper atoms, we need to use the molar mass of copper sulfate and Avogadro's number. According to the periodic table, the molar mass of copper is 63.54 g/mol, and the molar mass of CuSO4 is 159.62 g/mol. First, we find out how many moles of CuSO4 are in 320 grams:
320 g CuSO4 / 159.62 g/mol = 2.005 moles CuSO4
Since each mole of CuSO4 contains one mole of copper atoms, we then multiply the number of moles of CuSO4 by Avogadro's number (6.02 × 1023 atoms/mol) to get the number of copper atoms:
2.005 moles CuSO4 × 6.02 × 1023 atoms/mol = 1.206 × 1024 Cu atoms
Therefore, 320 grams of copper sulfate contains approximately 1.206 × 1024 copper atoms.