18.4k views
1 vote
How many moles of Fe₂O₃ will be produced from 27.0g of Fe assuming O2 is available in excess?

1 Answer

1 vote

Final answer:

To find the moles of Fe₂O₃ produced from 27.0g of Fe, we can use the balanced chemical equation and stoichiometric ratios.

Step-by-step explanation:

To find the moles of Fe₂O₃ that will be produced from 27.0g of Fe, we need to use the balanced chemical equation and stoichiometric ratios. The balanced equation for the reaction is:

Fe + 1.5O₂ → Fe₂O₃

In this equation, the ratio is 1:1, meaning that for every 1 mole of Fe, 1 mole of Fe₂O₃ is produced.

We need to convert the grams of Fe to moles by using the molar mass of Fe (55.85g/mol).

27.0g Fe × (1 mol Fe / 55.85g Fe) = 0.483 mol Fe

Therefore, 0.483 moles of Fe will produce 0.483 moles of Fe₂O₃.

User Ammar Abdullah
by
8.2k points