Question

During an experiment, the temperature of a solution changes from 9 4/5°F to 17 1/4°F.

What is the percent of increase in the temperature of the solution?

Answer 1

The percent of increase in the temperature of the solution when changing from 9 4/5°F to 17 1/4°F is approximately 76.02%.

Step-by-step explanation:

To calculate the percent of increase in the temperature of a solution, you first need to find the difference in temperature and then divide that by the original temperature. Here, the temperature changes from 9 4/5°F to 17 1/4°F.

First, convert the mixed numbers to improper fractions:

• 9 4/5°F = 49/5°F
• 17 1/4°F = 69/4°F

Next, find the difference in temperature:

(69/4°F) - (49/5°F) = (345/20°F) - (196/20°F)

= 149/20°F

Now, convert the difference back to a mixed number:

149/20°F = 7 9/20°F

Then, divide the temperature change by the original temperature and multiply by 100 to get the percent increase:

(7 9/20°F) / (9 4/5°F) × 100 = (7.45°F) / (9.8°F) × 100 ≈ 76.02%