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"A person pulls a 27kg sled with a force of 115 N, and a frictional force of 25 N also acts on the sled. The rope that she is pulling is at a 23 degree angle to the horizontal.

What is Net Frixtion?

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Final answer:

To calculate the net friction referred to in the student's question, we subtract the frictional force (25 N) from the pulling force (115 N). The net frictional force on the sled is therefore 90 N.

Step-by-step explanation:

The net friction in the context of the question is the difference between the total force applied on the sled and the force of friction acting in the opposite direction. Since a person is pulling a sled at an angle, you would need to consider only the horizontal component of the pulling force when calculating the acceleration. However, the question seems to have a typo and does not ask for this. It seems to ask for the net friction without considering the angle, which would typically be incorrect, but given the question asks specifically for 'Net Frixtion', we take this to mean the net frictional force acting on the sled, which is the difference between the pulling force and the frictional force opposing the motion.

To find the net frictional force, we can subtract the frictional force from the total force. If the pulling force includes both the horizontal component and frictional component, net friction (or the net frictional force) would be:

115 N (pulling force) - 25 N (frictional force) = 90 N

Thus, the net frictional force acting on the sled is 90 N.

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