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At a local pet store there are a total of 7 cats and dogs available for

adoption. There is one more than twice as many dogs as cats. If x represents the number of cats and y represents the number of dogs,
how many cats and dogs are available for adoption at the pet store?

User Genine
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1 Answer

4 votes

Final answer:

To find the number of cats and dogs available for adoption at the pet store, we can set up a system of equations. Solving the system of equations, we find that there are 2 cats and 5 dogs available for adoption.

Step-by-step explanation:

To solve this problem, we can set up a system of equations based on the given information. Let x represent the number of cats and y represent the number of dogs. We are given two pieces of information: there are a total of 7 cats and dogs available for adoption, and there is one more than twice as many dogs as cats.

We can set up the following equations:

x + y = 7

y = 2x + 1

Substituting the second equation into the first equation:

x + (2x + 1) = 7

Combining like terms:

3x + 1 = 7

Subtracting 1 from both sides:

3x = 6

Dividing both sides by 3:

x = 2

Now, we can substitute the value of x back into one of the equations to find the value of y:

y = 2(2) + 1 = 5

Therefore, there are 2 cats and 5 dogs available for adoption at the pet store.