Question

A rocket floats next to an interplanetary space station far from any planet. It ignites its engine. In Find the rocket's velocity 2.0 s after launch. the first second of its flight, it ejects 1/60 of its mass Express your answer in meters per second as an integer. with a relative velocity magnitude of 3300 m/s. Find its acceleration.

Answer 1

To find the rocket's velocity 2.0 s after launch, we can use the concept of conservation of momentum. The rocket's velocity 2.0 s after launch is 198000 m/s.

Step-by-step explanation:

To find the rocket's velocity 2.0 s after launch, we can use the concept of conservation of momentum. Since the rocket is in deep space far from any planet, there are no external forces acting on it. Therefore, the momentum of the rocket before and after the engine ignition should be the same. The initial momentum of the rocket is given by the product of its mass and velocity, which is equal to the final momentum after ejecting some mass and gaining velocity.

Let the initial mass of the rocket be M and its initial velocity be V. After ejecting 1/60 of its mass, the remaining mass of the rocket is (59/60)M. Since the rocket has gained a velocity of 3300 m/s relative to its previous velocity, the final velocity of the rocket after 2.0 s is given by:

V + 3300 = [(59/60)M / M] * V

Simplifying this equation, we can solve for V:

V = (3300 * 60) / (60 - 59) = 198000 m/s