Final answer:
To calculate the speed at which volcanic materials left a volcano and were sent 1.1 × 10⁴ m into the atmosphere, we would need the launch angle or additional information. Without it, we cannot accurately calculate this speed in m/s or convert it to km/h.
Step-by-step explanation:
The question involves a composite volcano that erupted, sending volcanic materials 1.1 × 10⁴ m into the atmosphere. To find the speed at which the materials left the volcano, we would typically use the kinematic equation for motion under constant acceleration. Since we ignore air resistance and assume a uniform gravitational field, the relevant equation is:
h = (v² × sin²(θ)) / (2g)
Where h is the maximum height (1.1 × 10⁴ m), v is the initial velocity, θ is the launch angle, and g is the acceleration due to gravity (9.81 m/s²).
However, the information provided is not sufficient to calculate the initial velocity as neither the launch angle nor the initial velocity direction is given. If we assume that the eruption sends materials vertically upwards, the angle would be 90° and the equation simplifies to:
h = v² / (2g)
This can be rearranged to solve for the initial velocity (v), but we don't have enough information to complete this calculation.
To calculate the speed in km/h, we could multiply the velocity in m/s by 3.6.