Question

A golf ball with mass .05 kg is sitting on a tee. It is struck with a club horizontally. The ball leaves the face of the club with a velocity of +44.0 m/s. What is the magnitude of the impulse of the collision?

a. 0.05Ns
b. 10.0Ns
c. 2.2Ns
d. 22.0NS

Answer 1

The magnitude of the impulse of the collision is 2.2 Ns.

Step-by-step explanation:

The impulse of a collision can be calculated by multiplying the change in momentum of the object by the time it takes for the change to occur. In this case, the golf ball has an initial velocity of +44.0 m/s and comes to rest after the collision, so the change in momentum is equal to the initial momentum. The initial momentum is calculated by multiplying the mass of the golf ball (0.05 kg) by the initial velocity (+44.0 m/s), giving a value of +2.2 kg*m/s. Therefore, the magnitude of the impulse of the collision is 2.2 Ns, which corresponds to option c.