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Find the equation of line passing through (1,-15) and (-6,-1).

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Final answer:

The equation of the line passing through the points (1, -15) and (-6, -1) is y = -2x - 13.

Step-by-step explanation:

To find the equation of a line passing through two points, we can use the formula for the slope (m) of the line, which is m = (y2 - y1) / (x2 - x1), where (x1, y1) and (x2, y2) are the coordinates of the two points. After calculating the slope, we can use the point-slope form of a line's equation, which is y - y1 = m(x - x1), to find the specific equation of our line.

Now, let's calculate the slope using the points (1, -15) and (-6, -1). The slope m would be:

m = (-1 + 15) / (-6 - 1) = 14 / -7 = -2

Now, using the point-slope form with point (1, -15) and slope m = -2, we get:

y - (-15) = -2(x - 1)

Our equation of the line is:

y + 15 = -2x + 2

After further simplifying:

y = -2x - 13

This is the final equation of the line.

User Thi Tran
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