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Two light bulbs (1 and 2) are connected in serles, and then the combination is connected across the terminals of a battery. Each connecting wire has zero resistance. The resistance of 1 is greater than the resistance of 2 . Which statement is true? Multiple Choice

a. The power dissipated by 1 is greater than the power dissipated by 2 .
b. The power dissipated by 1 is less then the power dissipated by 2
c. The power dissipated by 1 is equal to the power dissipated by 2

User Griwes
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Final answer:

In a series circuit, two light bulbs with different resistances dissipate equal power because they have the same current flowing through them, even though their resistances are not the same.

Step-by-step explanation:

When two light bulbs with different resistances are connected in series and then connected across a battery, the true statement is that the power dissipated by bulb 1, which has greater resistance, is equal to the power dissipated by bulb 2, which has less resistance. This is because, in a series circuit, the current through both bulbs is the same. The power dissipated in a resistor is given by the formula P = I²R, where P is power, I is current, and R is resistance. As both light bulbs are connected in series, they will have identical currents flowing through them; thus the power dissipation is equal for both, despite the differing resistances.

User Dribbel
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