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Considering an extreme relativistic ideal gas in volume V in equilibrium with the environment of temperature T. The gas is consisting of N non-interacting monatomic molecules with the single particle energy ε=pc, where c is the speed of light. The single-particle energy state in the range of p to (p+dp) is 4πVp²dp. Find the partition function.

User Jon Rubins
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Final answer:

The question involves finding the partition function for an extreme relativistic ideal gas with energy ε = pc. It involves integrating over momentum states weighted by the Boltzmann factor e-ε/kT to find Z, and then raising Z to the power of N for N non-interacting particles.

Step-by-step explanation:

The student is asked to find the partition function for an extreme relativistic ideal gas consisting of non-interacting monatomic molecules. This scenario falls within the realm of statistical mechanics and quantum physics. The single-particle energy ε is given as ε = pc (where p is momentum and c is the speed of light). The number of states in the momentum range p to p+dp is given by 4πVp²dp. The partition function Z for one particle in the volume V at temperature T is calculated by integrating the Boltzmann factor e-ε/kT over all momentum states, where k is the Boltzmann constant. Since ε = pc and the energy states are 4πVp²dp, the partition function becomes:


Z = ∫0∞ 4πVp² e-pc/kT dp

This integral needs to be calculated to obtain the partition function for one particle. After finding Z for one particle, the partition function for all N particles, assuming they are non-interacting and distinguishable, would be ZN, as each particle contributes independently to the total partition function

User Jeremy Kerr
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