Final answer:
The momentum of the stick at the top of its trajectory is 0.0 kg m/s because it has a velocity of 0 m/s at that point, resulting in zero momentum.
Step-by-step explanation:
The student's question is about determining the momentum of a stick at the top of its trajectory when thrown into the air. Momentum is given by the equation p = mv, where p is momentum, m is mass, and v is velocity. At the top of the path, the velocity of the stick is 0 m/s because it momentarily stops before starting to fall back down. Therefore, the momentum of the stick at the top is also 0.0 kg m/s since multiplying the mass (0.02 kg) by the velocity (0 m/s) equals zero.