Final answer:
The magnitude of the magnetic field created by a wire carrying a 2.0-A current, at a distance of 0.60 m from the wire, can be calculated using Ampère's law and is B = 6.67 × 10^-7 T.
Step-by-step explanation:
The question you are asking pertains to the magnetic field created by a current-carrying wire, which is a fundamental concept in Physics, specifically electromagnetism. According to Ampère's law and the Biot-Savart Law, a long straight wire carrying a current generates a magnetic field around it that is proportional to the current and inversely proportional to the distance from the wire.
The magnetic field B at a point a distance r from a long straight wire carrying current I is given by the equation B = (μ0/2π) * (I/r), where μ0 is the magnetic constant (permeability of free space), which is approximately 4π × 10^-7 T·m/A. Using this formula for a wire carrying a 2.0-A current located along the y-axis, the magnitude of the magnetic field at a point 0.60 m along the x-axis would be B = (μ0/2π) * (2.0 A / 0.60 m).
After calculations, the magnetic field strength at the specified point would be B = 6.67 × 10^-7 T (teslas).