Question

A ball with a mass of 0.150 kg is dropped from rest from a height of 1.25 m. The ball rebounds with an impulse by the floor on the ball of 1.39 Ns upward. What is the rebound velocity of the ball?

a. 2.85 m/s
b. 4.37 m/s
c. 14.2 m/s
d. 16.7 m/s

Answer 1

To find the rebound velocity of the ball, we can use the principle of conservation of momentum. By rearranging the equation and substituting the given values, we can solve for the final velocity. The rebound velocity of the ball is approximately 9.27 m/s.

Step-by-step explanation:

To find the rebound velocity of the ball, we can use the principle of conservation of momentum. The initial momentum of the ball can be calculated using the equation:

Initial momentum = mass x initial velocity

The ball is dropped from rest, so its initial velocity is 0. When the ball rebounds, the impulse by the floor on the ball can be used to find the final velocity. The impulse is calculated using the equation:

Impulse = change in momentum = mass x change in velocity

By rearranging the equation and substituting the given values, we can solve for the final velocity:

Final velocity = (Impulse / mass) + initial velocity

Substituting the given values:

Final velocity = (1.39 Ns / 0.150 kg) + 0 = 9.27 m/s

Therefore, the rebound velocity of the ball is approximately 9.27 m/s.