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An oxygen ion (O+) moves in the xy-plane with a speed of 2.30 ✕ 103 m/s. If a constant magnetic field is directed along the z-axis with a magnitude of 1.75 ✕ 10−5 T, find the magnitude of the magnetic force acting on the ion and the magnitude of the ion's acceleration. The magnitude (in N) of the magnetic force acting on the ion N

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Final answer:

To calculate the magnetic force on an oxygen ion and its acceleration, one must apply the equation for magnetic force (F = qvBsinθ) and Newton's second law (F = ma). However, without the charge of the ion, the exact values can't be determined.

Step-by-step explanation:

The question involves calculating the magnetic force acting on an oxygen ion moving in the xy-plane and its resulting acceleration. Using the formula F = qvBsinθ, where F is the magnetic force, q is the charge of the ion, v is the speed of the ion, B is the magnetic field, and θ is the angle between the velocity vector and the magnetic field vector, one can calculate the force. Since the ion is moving in the xy-plane and the magnetic field is along the z-axis, the angle θ is 90 degrees, and sinθ is 1. For the acceleration, apply Newton's second law, F = ma, where m is the mass of the ion and a is the acceleration. Without the actual charge of the oxygen ion, the exact values for force and acceleration cannot be determined.

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