Final answer:
The velocity of a 2kg rabbit with a kinetic energy of 1.5625 J is 1.25 m/s, calculated using the kinetic energy formula and rearranging it for velocity.
Step-by-step explanation:
To calculate the velocity of a 2kg rabbit hopping with a kinetic energy (KE) of 1.5625 J, we can use the kinetic energy formula:
KE = ½ mv²
where:
- KE is kinetic energy,
- m is the mass of the object,
- v is the velocity of the object.
Rearranging for velocity (v), we get:
v = √(2KE/m)
By substituting in the known values:
v = √(2*1.5625 J / 2 kg)
v = √(1.5625 J / 1 kg)
v = √1.5625 m²/s²
v = 1.25 m/s
Thus, the velocity of the rabbit is 1.25 m/s.