Final answer:
The code segment provided uses a repeat-until loop combined with a counter, which results in the output 'and 1 and 2 and 3'. The loop ends when the counter reaches 3.
Step-by-step explanation:
The code provided is a simple control structure that increments a counter in a loop and displays text and the current value of the counter until a specified condition is met. When we run through the code, we start with Count = 0. The 'Repeat until' loop runs, increments Count by 1, and then displays "and" followed by the current value of Count. This process repeats until Count equals 3.
On the first run, Count becomes 1 and "and 1" is displayed. On the second run, Count becomes 2 and "and 2" is added to the output. On the third run, Count becomes 3 and "and 3" is added to the output. After this, since Count equals 3, the loop terminates. The final output will display in sequence without spaces between iteration outputs, resulting in the string: "and 1 and 2 and 3". Therefore, the correct answer is b. "and 1 and 2 and 3".