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The solubility of Ag₂CO₃ in water at 25 °C is measured to be 0.035 g/L. Use this information to calculate Ksp for Ag₂CO₃.

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Final answer:

To calculate the solubility product constant (Ksp) for Ag₂CO₃, we need to determine the concentration of Ag⁺ ions and CO₃²⁻ ions in the solution. The solubility of Ag₂CO₃ is given as 0.035 g/L at 25 °C. Using this information, we can calculate the concentrations of Ag⁺ and CO₃²⁻ ions and substitute them into the expression for Ksp.

Step-by-step explanation:

To calculate the solubility product constant (Ksp) for Ag₂CO₃, we need to determine the concentration of Ag⁺ ions and CO₃²⁻ ions in the solution. The solubility of Ag₂CO₃ is given as 0.035 g/L at 25 °C.

Using this information, we can calculate the concentrations of Ag⁺ and CO₃²⁻ ions and substitute them into the expression for Ksp.

The balanced equation for the dissolution of Ag₂CO₃ is:

Ag₂CO₃ ⇌ 2Ag⁺ + CO₃²⁻

From the equation, we can see that the concentration of Ag⁺ ions ([Ag⁺]) is equal to twice the solubility of Ag₂CO₃, and the concentration of CO₃²⁻ ions ([CO₃²⁻]) is equal to the solubility of Ag₂CO₃.

Therefore, [Ag⁺] = 2(0.035 g/L)

= 0.07 g/L and

[CO₃²⁻] = 0.035 g/L.

Now, we convert the concentrations from grams per liter to molarity by dividing by the molar mass of Ag and CO₃.

The molar mass of Ag is 107.87 g/mol, and the molar mass of CO₃ is 60.01 g/mol.

Thus, [Ag⁺] = 0.07 g/L / 107.87 g/mol

= 6.48 × 10⁻⁴ M and

[CO₃²⁻] = 0.035 g/L / 60.01 g/mol

= 5.83 × 10⁻⁴ M.

Finally, we substitute these concentrations into the expression for Ksp:

Ksp = [Ag⁺]²[CO₃²⁻]

= (6.48 × 10⁻⁴ M)²(5.83 × 10⁻⁴ M)

≈ 2.1 × 10⁻¹⁰

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