Question

If Luis pulls straight down on the end of a wrench that is tilted θ = 30∘ above the horizontal and is r = 35 cm long, what force must he apply to exert a torque of -17 N⋅m?

Answer 1

To exert a torque of -17 N⋅m on a wrench tilted at 30 degrees above the horizontal and with a length of 35 cm, Luis must apply a force of -108.63 N.

Step-by-step explanation:

To find the force Luis must apply to exert a torque of -17 N⋅m, we can use the equation for torque: T = rFsin(theta). In this equation, T is the torque, r is the length of the wrench, F is the force applied, and theta is the angle between the wrench and the horizontal. Given that the wrench is tilted at an angle of 30 degrees and the torque is -17 N⋅m, we can rearrange the equation to solve for F.

Using the given values, we have:

-17 N⋅m = (0.35 m)(F)(sin 30°)

Simplifying the equation, we find:

F = -17 N⋅m / (0.35 m)(sin 30°) = -108.63 N

Therefore, Luis must apply a force of -108.63 N to exert a torque of -17 N⋅m on the wrench.