Final answer:
To find the solution of the given system of equations x' = -4y and y' = 2x, we differentiate the first equation and substitute the value of y'. This leads to a second-order linear homogeneous differential equation with the solution x(t) = c1 cos(√8t) + c2 sin(√8t), where c1 and c2 are constants.
Step-by-step explanation:
The given system of equations is:
x' = -4y
y' = 2x
To find the solution, we can differentiate the first equation with respect to t:
x'' = -4y'
Substitute the value of y' from the second equation:
x'' = -4(2x)
x'' = -8x
This is a second-order linear homogeneous differential equation. The solution is given by x(t) = c1 cos(√8t) + c2 sin(√8t), where c1 and c2 are constants.