Question

At a certain temperature the following reactions have the constants shown.

S(s) + O₂(g) SO₂(g) K'c = 4.2 1052
2 S(s) + 3 O₂(g)₂ SO₃(g) K"c = 9.8 10128

Calculate the equilibrium constant Kc for the following reaction at that temperature.
2 SO₂(g) + O₂(g)₂ SO₃(g)

Answer 1

To find the equilibrium constant (Kc) for the reaction 2 SO₂(g) + O₂(g) ⇒ 2 SO₃(g), insert the given equilibrium concentrations into the Kc expression and calculate the value, which turns out to be 4.2.

Step-by-step explanation:

To calculate the equilibrium constant (Kc) for the reaction 2 SO₂(g) + O₂(g) ⇒ 2 SO₃(g) given equilibrium concentrations of SO₂, O₂, and SO₃, we use the expression for Kc:

Kc = [SO₃]² / ([SO₂]² × [O₂])

Substituting the given concentrations:

Kc = (1.1 M)2 / ((0.90 M)² × 0.35 M)

This calculation results in Kc = (1.12 / (0.902 × 0.35)), which simplifies to Kc = (1.21 / (0.81 × 0.35)).

After performing the calculation we find that Kc = 4.2