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if 1oz of icing costs $0.14 and can cover 4in^2, how much would it cost for me to cover the entire gingerbread house in icing? the gingerbread house surface area is 65.45in^2?

User Agl
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1 Answer

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Final answer:

To cover a gingerbread house that has a surface area of 65.45in^2, it would cost approximately $2.29, given that 1oz of icing costs $0.14 and covers 4in^2.

Step-by-step explanation:

The question involves calculating the cost of icing needed to cover the entire surface area of a gingerbread house in terms of Mathematics. To find the total cost, we first need to determine how much icing is required for the given surface area.

The cost for 1oz of icing, which covers 4in2, is $0.14. The gingerbread house has a surface area of 65.45in2. Thus, we can calculate the amount of icing needed using proportions:

1oz icing / 4in2 = X oz icing / 65.45in2

Solving for X gives us the amount of icing in ounces needed to cover the gingerbread house:

X = (65.45in2 / 4in2) * 1oz

Next, we calculate the total cost by multiplying the amount of icing needed by the cost per ounce:

Cost = X * $0.14

Finally, we do the math to find the answer:

X = 65.45 / 4 = 16.3625oz

Cost = 16.3625oz * $0.14/oz = $2.291

Therefore, it will cost approximately $2.29 to cover the entire gingerbread house with icing.

User Juan Elfers
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