77.2k views
0 votes
An infinitely long line of charge has a linear charge density of 3.50×10⁻¹²C/m. A proton is at distance 19.0 cm from the line and is moving directly toward the line with speed 1900 m/s. How close does the proton get to the line of charge?

User Joseph B
by
8.0k points

1 Answer

3 votes

Final answer:

The problem asks how close a proton will get to an infinitely long line of charge given a specific linear charge density and the proton's initial dynamics. Using conservation of energy, equating the proton's initial kinetic energy with its potential energy at the closest point to the line of charge allows us to solve for the distance of closest approach.

Step-by-step explanation:

The student is asking how close a proton will get to an infinitely long line of charge given its linear charge density and the proton's initial speed and distance from the line. This question involves the concepts of electricity, electric fields, and kinetic and potential energy.

To solve this problem, we use the principle of energy conservation. The proton's initial kinetic energy will be converted into electrical potential energy as it approaches the line of charge. Therefore, we can set the initial kinetic energy equal to the potential energy at the point of closest approach (assuming the potential energy at infinity to be zero and ignoring any forces other than the electric force).

The initial kinetic energy (KE) of the proton is given by:

KE = (1/2)mv2

where m is the mass of the proton and v is its initial speed.

The electric potential energy (U) at a distance r from the line charge is given by:

U = 2πε0λ(r)

where λ is the linear charge density and ε0 is the permittivity of free space. The function λ(r) represents the work done per unit charge by the electric field to bring the proton from infinity to a distance r from the line of charge.

Setting the KE equal to U, we solve for <>r to find the distance of closest approach. We can use a definite integral to evaluate λ(r) from the starting position to the point of closest approach, since the force varies with distance.

Since the integral calculation and algebra can be extensive, it is not shown here, but following these steps will lead to the answer. Note that we are considering only the electrostatic force and assuming that the proton's path is directly towards the line of charge without any other forces involved.

User Onepiece
by
7.8k points