Question

An object undergoes free-fall. its initial speed is 4.90 m/s. what is its final speed after falling for 2.0 s, use g = 9.80 m/s² as the magnitude of the acceleration due to gravity.

Answer 1

The final speed of an object undergoing free-fall with an initial speed of 4.90 m/s after falling for 2.0 seconds is 24.50 m/s, using the formula V = V0 + at, with the acceleration due to gravity being 9.80 m/s².

Step-by-step explanation:

To calculate the final speed of an object in free-fall after 2.0 seconds, we can use the following kinematic equation for uniformly accelerated motion:

V = V0 + at

Where:

• V is the final velocity
• V0 is the initial velocity
• a is the acceleration due to gravity
• t is the time the object has been falling

In this case:

• V0 = 4.90 m/s (downward)
• a = 9.80 m/s2
• t = 2.0 s

Substituting the given values into the equation gives us:

V = 4.90 m/s + (9.80 m/s2 × 2.0 s)

V = 4.90 m/s + 19.60 m/s

V = 24.50 m/s

The final speed of the object after falling for 2.0 seconds is 24.50 m/s.