Question

A 1500 kg car starts from rest and drives around a flat 66-m -diameter circular track. The forward force provided by the car's drive wheels is a constant 1200 N .

What is the direction of the car's acceleration at t=11s? Give the direction as an angle from the r-axis

Answer 1

The car's acceleration is directed towards the center of the circular track.

Step-by-step explanation:

The car is traveling in a circular motion, so its acceleration is directed towards the center of the circle. The direction of acceleration can be determined using the centripetal acceleration formula: a = v^2 / r, where a is the centripetal acceleration, v is the velocity, and r is the radius of the circular track. In this case, the diameter of the track is given, so we can calculate the radius: r = d / 2 = 66 m / 2 = 33 m. The velocity of the car can be obtained by dividing the distance traveled by the time taken: v = d / t = 2πr / t = 2π(33 m) / 11 s ≈ 18.85 m/s. Plugging these values into the centripetal acceleration formula, we get: a = (18.85 m/s)^2 / 33 m ≈ 10.7 m/s^2. Therefore, the direction of the car's acceleration at t = 11s is directed towards the center of the circular track.