Question

A rectangular loop of wire of width (↔)18 cm and length (↑)12 cm is placed in a region where the magnetic field is 345 Teslas in strength as shown in the figure below (the North and South poles of the magnet are indicated in the figure by the N and S letters). A current of 4.2Amps flows CCW (counter-clockwise) as viewed from above through the wire. Use the direction convention indicated on the first page (N↑,E→,S↓,W←, up ⊙, down ⊗)

a) What will be the magnetic force on the West side of the loop? Magnitude: direction:

Answer 1

The magnetic force on the West side of the rectangular loop of wire is calculated as 260.19 Newtons, directed out of the page (⊕), based on the magnitude of the current, length of the wire, and strength of the magnetic field, using the right-hand rule.

Step-by-step explanation:

To determine the magnetic force on the West side of the rectangular loop of wire placed in a magnetic field, we use the formula F = I L B, where F is the force, I is the current, L is the length of the wire in the field, and B is the magnetic field strength. I

n this case, the wire has a current of 4.2 Amps, a length of 18 cm (0.18 m), and the magnetic field strength is 345 Teslas. 'The force can be calculated as follows:

F = I L B
F = 4.2 A × 0.18 m × 345 T
F = 260.19 N

The direction of the force can be determined using the right-hand rule.

The thumb points in the direction of the current (West to East for the West side of the loop), and the fingers point in the direction of the magnetic field (North to South).

The palm then points in the direction of the force, which in this case will be ⊕ (out of the page) since the current flows counter-clockwise as viewed from above.