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68% of U.S. adults have very little confidence in newspapers. You randomly select 10 U.S. adults. Find the probability that the number of U.S. adults who have very little confidence in newspapers is exactly five,

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Final answer:

The question involves calculating a binomial probability for exactly five out of ten U.S. adults to have very little confidence in newspapers. We use the binomial probability formula with n = 10 trials, k = 5 successes, and p = 0.68 as the probability of success on a single trial. The solution is found by computing the combination of 10 items taken 5 at a time, and then multiplying by the probabilities of success and failure raised to the appropriate powers.

Step-by-step explanation:

The question at hand involves calculating the probability of exactly five out of ten U.S. adults having very little confidence in newspapers, given that 68% of U.S. adults hold this view. This is a binomial probability problem where we want to find the probability of exactly 5 successes (adults with little confidence) out of 10 trials (the adults surveyed), with the probability of success on a single trial being 0.68. We use the binomial probability formula:

P(X = k) = C(n, k) * p^k * (1-p)^(n-k)

Where:

  • C(n, k) is the combination of n items taken k at a time.
  • p is the probability of success on a single trial.
  • k is the number of successes.
  • n is the total number of trials.

Plugging the values into the formula, we get:

P(X = 5) = C(10, 5) * 0.68^5 * (1-0.68)^5

Calculating the combination C(10, 5) and then multiplying by the probabilities raised to their respective powers of successes and failures will give us the desired probability of this event occurring.

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