Question

Two cyclists leave towns 160 kilometers apart at the same time and travel toward each other. One cyclist travels 4(km)/(h) slower than the other. If they meet in 4 hours, what is the rate of each cyclist? Rate of the slower cyclist: (km)/(h) Rate of the faster cyclist: (km)/(h)

Answer 1

The rate of the slower cyclist is 18 km/h and the rate of the faster cyclist is 22 km/h.

Step-by-step explanation:

In this problem, we have two cyclists traveling towards each other. Let's denote the rate of the slower cyclist as x km/h. Since the other cyclist is 4 km/h faster, their rate would be (x + 4) km/h.

Using the formula: distance = rate x time, we can set up the equation:
(x km/h) x (4 hours) + [(x + 4) km/h] x (4 hours) = 160 km

Simplifying this equation, we get:
4x + 4(x + 4) = 160
8x + 16 = 160
8x = 144
x = 18 km/h

Therefore, the rate of the slower cyclist is 18 km/h and the rate of the faster cyclist is 22 km/h.