Final answer:
The current required to produce a 0.425mT magnetic field in the solenoid with 800 turns and 43.0 cm in length is approximately 0.50 A, calculated using the formula for the magnetic field inside a solenoid.
Step-by-step explanation:
The student has asked about the current required to produce a specific magnetic field in a solenoid. The magnetic field inside a solenoid (B) is given by the formula B = μ₀ * (N/L) * I, where μ₀ is the permeability of free space (μ₀ = 4π x 10⁻⁷ T·m/A), N is the number of turns, L is the length of the solenoid, and I is the current in amperes.
To find the current (I) for this solenoid, we rearrange the formula to solve for I: I = B * L / (μ₀ * N). Substituting values, we get I = 0.425 x 10⁻³ T * 0.43 m / (4π x 10⁻⁷ T·m/A * 800). After calculating, the current required is found to be approximately 0.50 A.