Question

The left ventricle of the heart accelerates blood from rest to a velocity of +22.2 cm/s. (a) If the displacement of the blood during the acceleration is +1.62 cm, determine its acceleration (in cm/s²)

Answer 1

To determine the acceleration of blood in the left ventricle of the heart, we can use the equation v² = u² + 2as. Plugging in the given values, we find that the acceleration is 541.92 cm/s².

Step-by-step explanation:

In this problem, we need to determine the acceleration of blood in the left ventricle of the heart. We are given the initial velocity, final velocity, and displacement of the blood. We can use the equation:

v² = u² + 2as

Where v is the final velocity, u is the initial velocity, a is the acceleration, and s is the displacement. Rearranging the equation to solve for acceleration, we have:

a = (v² - u²) / (2s)

Plugging in the given values, we get:

a = ((+22.2 cm/s)² - 0²) / (2 * 1.62 cm)

Simplifying the equation, we get:

a = 541.92 cm/s²

Therefore, the acceleration of the blood is 541.92 cm/s².