Final Answer:
There is enough evidence to reject the research center's claim at the 0.05 significance level.
Step-by-step explanation:
The null hypothesis (H0) is that 30% of adults in the country would travel into space on a commercial flight if they could afford it, and the alternative hypothesis (Ha) is that this proportion is not 30%. Mathematically, H0: p = 0.30 and Ha: p ≠ 0.30, where p represents the proportion of adults willing to travel into space. The significance level (α) is given as 0.05.
To test the hypothesis, we use a z-test for proportions. In this case, the sample proportion is 33% or 0.33, and the sample size is 700. The formula for the z-test is given by:
![\[ z = \frac{{\hat{p} - p}}{{\sqrt{\frac{{p(1-p)}}{{n}}}}} \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/8sxb470us8tqtpx7nark8u71gzq1ieml3s.png)
Where
is the sample proportion, p is the hypothesized population proportion, and n is the sample size.
Substituting the values, we get:
![\[ z = \frac{{0.33 - 0.30}}{{\sqrt{\frac{{0.30(0.70)}}{{700}}}}} \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/fc9arxm6bjzxdmwb6jslycbvdz8lt9sqx2.png)
After calculating the z-value, we compare it to the critical z-value at a 0.05 significance level. If the calculated z-value falls outside the critical region, we reject the null hypothesis.
In this case, the calculated z-value exceeds the critical value, indicating that the observed proportion of adults willing to travel into space is significantly different from the claimed 30%. Therefore, there is enough evidence to reject the research center's claim.