The point I(-2/3, -1/3) on the coordinate plane is added as an attachment
Graphing the points on the coordinate plane.
From the question, we have the following parameters that can be used in our computation:
I(-2/3, -1/3)
So, we have
x = -2/3
y = -1/3
Using the above as a guide, we have the following:
I(-2/3, -1/3) is -2/3 units to the left of the origin and 1/3 units below it
So, we plot the graph
See attachment for the point on a coordinate plane